(2x^-8/y^-2)^-3

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Solution for (2x^-8/y^-2)^-3 equation: 


D( x )

x = 0

(2*x^-8)/(y^-2) = 0

y^-2 = 0

x = 0

x = 0

(2*x^-8)/(y^-2) = 0

(2*x^-8)/(y^-2) = 0

2*x^-8*y^2 = 0 // : 2*y^2

x^-8 = 0

x należy do O

y^-2 = 0

y^-2 = 0

y^-2 = 0

x należy do R

x belongs to the empty set

((2*x^-8)/(y^-2))^-3 = 0

x belongs to the empty set

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